b^2-5b-16=-80

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Solution for b^2-5b-16=-80 equation:


Simplifying
b2 + -5b + -16 = -80

Reorder the terms:
-16 + -5b + b2 = -80

Solving
-16 + -5b + b2 = -80

Solving for variable 'b'.

Reorder the terms:
-16 + 80 + -5b + b2 = -80 + 80

Combine like terms: -16 + 80 = 64
64 + -5b + b2 = -80 + 80

Combine like terms: -80 + 80 = 0
64 + -5b + b2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-64' to each side of the equation.
64 + -5b + -64 + b2 = 0 + -64

Reorder the terms:
64 + -64 + -5b + b2 = 0 + -64

Combine like terms: 64 + -64 = 0
0 + -5b + b2 = 0 + -64
-5b + b2 = 0 + -64

Combine like terms: 0 + -64 = -64
-5b + b2 = -64

The b term is -5b.  Take half its coefficient (-2.5).
Square it (6.25) and add it to both sides.

Add '6.25' to each side of the equation.
-5b + 6.25 + b2 = -64 + 6.25

Reorder the terms:
6.25 + -5b + b2 = -64 + 6.25

Combine like terms: -64 + 6.25 = -57.75
6.25 + -5b + b2 = -57.75

Factor a perfect square on the left side:
(b + -2.5)(b + -2.5) = -57.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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